Find the equation of a plane passing through the points A (2, 2, –1), B (3, 4, 2) and C (7, 0, 6) in non
parametric form.
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
Sol. We know that equation of the plane in non- parametric form, when it passes through three given points, is
. ( 
× 
+ 
× 
+ 
× 
) = [ 
] …(i)
Here 
= 2 
+ 2 
– 
, 
= 3 
+ 4 
+ 2 
and 
= 7 
+ 6 
Now substituting the values of 
, 
and 
in equation (i), we get
. 
= 
. [{ 
(4 + 4) – 
(4 + 3) + 
(8 – 6)} + { 
(24 – 0) –
(18 – 14) + 
(0 – 28)} + { 
(0 – 12) – 
(–7 –12) +
(14 – 0)}= {2 (24 – 0) – 2 (18 – 14) + (–1) (0 – 28)}
= 
. [8 
–7 
+ 2 
+ 24 
–4 
–28 
–12 
+ 19 
+ 14 
] = 68
= 
. [20 
+ 8 
– 12 
] = 68
= 
. [5 
+ 2 
– 3 
] = 17
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems